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| [5050 lamp beads] LED lamp beads light flux lighting calculation method |
| Time:2022-10-08 00:00:00 | view： |
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LED lamp beads lighting lit light calculation method I have seen a lot of LED lighting masters. They pay great attention to LED lamp bead lighting calculations. In their LED lamp bead lighting schemes Simulation calculation. Moreover, the more complicated the space, the more you need to perform lighting calculations. As a quantitative design method, the illumination calculation is indispensable on most occasions. If there are some errors, it is not difficult to find the necessary illuminance by calculating the LED lamp bead lighting design. Today we will introduce two methods. 1, LED light flux method LED lamp beads light flux method is mainly used in the equivalence of the LED lighting lamp space, calculated when calculating the average illuminance, in addition to the use space such as office and factories, in restaurants, restaurants, houses, etc. In the space of the atmosphere, in order to confirm the approximate degree of illumination, it is convenient to use this LED illumination calculation method.2, LED one -by -point calculation of the calculation of the calculation of the computing algorithm is used when calculating the actual degree required for local lighting and the key display part. When the LED lamp beads are calculated for the calculation of the light flux method of LED lamp beads, 1 When installing a 100W nude bulb of 500lm, it is assumed that 30 % of the light beam should be directly illuminated on the ground. So how much is the direct illumination on the ground? E \u003d f / a \u003d 1500 * 0.3 / 10 \u003d 45LX Except for the beams that are irradiated on the ground, other beams illuminate the ceiling and wall surface. If the reflectance of the ceiling and the wall is high, the reflected light will be added to the direct illumination of the ground, so the actual illumination is above 45LX. Most of the lamps for basic LED lighting are direct light -equipped downlight lighting and mixed lighting lamps with fluorescent lamps, as well as indirect lighting of ceiling light such as light glow grooves. The illumination calculation of direct light matching, the more the light is affected by the ceiling and wall reflectance. Even if the reflectance of the room is somewhat different, the average illumination error will be very small. However, if there are high partition walls and furniture, the calculation results of the shadow part of the shadow are deviated. In addition, the indirect LED lighting of the ceiling must not only be affected by the ceiling surface, but also greatly affected the wall reflectance rate. The distance from the ceiling is different, and the lighting utilization rate will change, so it is difficult to calculate without error. 舉例2 一棟正面開間8m，進深10m，室內(nèi)凈高2．4m的房間，為了使室內(nèi)的照明均勻，把20盞筒燈照明A燈具進行了整齊的排列配置，計算出此時The average illumination on the ground? (The reflectance of the room is the ceiling: 70 %, the wall: 50 %, the ground: 20 %) Room Space Index \u003d Kaima Room ＊ Deep / (Kaishou + in -depth) ＊ The height of the light source \u003d 10 * 8 / (10 ＋ 8) * 2. 4 \u003d 1.85 can be seen from the above figure that the room space index is roughly between 1.5 and 2.0, and the lighting utilization rate is about 0.6. Maintenance rate M, incandescent lamps are 0.7 to 0.9, fluorescent lamps are 0.65 to 0.75, and 0.8 here. E \u003d f * n * u * m / a \u003d 1520 * 20 * 0.6 * 0.8 \u003d 180lx Average multiplied by the light of the lamps within the value of H (high light source), which means on the ground or work surface There will be no uniform spots. Calculate the illumination of a specific pointSince the local lighting of hanging decoration and lighting lights is used, when calculating the direct horizontal plane strength or vertical surface illumination of a specific point, the illumination algorithm can be used. Example 3 As shown in the figure, when installing the B with the light lamp at the high (h) 2m, what is the level of the level of the level when the lower illumination and deviation from the 20 ° directly below? (COS320 ° 3 0.83) Vertical illuminance: P \u003d 1000 /4 \u003d 250LX Dist at the top of the level at the front of 20 °: P? \u003d 500 /4 * 0.83≈104lx Therefore, the brightness of local LED lighting As long as you know the lighting data, you can not only calculate the strength of the horizontal plane, but also simply calculate the vertical direct exposure intensity. Especially on the illumination distribution diagram of the outdoor roads and squares, and exterior wall LED lighting that are not reflected in each other, the LED illuminance is suitable for the computing algorithm. |
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